How do you simplify #(0.15)(3.2)#?

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Answer 1 · 2017-04-04T02:24:23

#.48# or #12/25#

Write each one as a fraction.

#0.15=15/100#

#3.2=320/100#

Now look at the problem:

#(15/100)(320/100)#

Now multiply the numerators and the denominators together:

#15xx320=4800#

#100xx100=10000#

So you have:

#4800/10000#

Get rid of two #0#s from both the numerator and denominator:

#48/100#

So as a decimal, this is #.48#. Or you could continue the simplify the fraction:

#48/100=12/25#

Answer 2 · 2017-04-04T02:32:29

.48

#.15 * 3.2 = .48#