Review this reaction: $H_2SO_4 + NaOH$ . What are th product(s)?

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Answer 1 · 2017-04-05T23:39:28

The products are $H_2O$ and $Na_2SO_4$ , since this is a double-replacement/neutralization reaction.

This is a double-replacement neutralization (acid-base) reaction:

The two $H$ atoms in $H_2SO_4$ would react with the hydroxide ion, $OH^-$ , in $NaOH$ to form water, $H_2O$ .

The $SO_4$ would react with $Na$ to form $Na_2SO_4$ .

$H_2SO_4+NaOH->H_2O +Na_2SO_4$

Review this reaction: H_2SO_4 + NaOHH_2SO_4 + NaOH. What are th product(s)?