Question #86fbc

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Question #86fbc

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Answer 1 · 2017-04-06T05:50:26

Use trig identity:
$(1 + {tan}^{2} t) = {sec}^{2} t$ $(1 + tan^2 t) = sec^2 t$
Develop the Left Side:
$L S = sin t (1 + {tan}^{2} t) = sin t . {sec}^{2} t = \frac{sin t}{{cos}^{2} t}$ $LS = sin t (1 + tan^2 t) = sin t.sec^2 t = sin t/(cos^2 t)$
$L S = (\frac{1}{cos t}) (\frac{sin t}{cos t}) = sec t . tan t$ $LS = ((1)/(cos t))((sin t)/(cos t)) = sec t.tan t$ . Proved

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Question #86fbc

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