The length of rectangle is 5 more than the width. The perimeter is 22 feet. How do you find the length and width?

2 Answers
Apr 6, 2017

#W = 11/6 " ft" = 1 " ft " 10 " inches" = 22 " inches"#
#L = 9 " ft " 2 " inches" = 110 " inches"#

Explanation:

Given: #L = 5W#, Perimeter #= 22 " ft"#

Perimeter, #P = 2L + 2W#

Substitute in your given values:
#22 = 2(5W) + 2W#

Distribute and solve for #W#:

#22 = 10W + 2 W#
#22 = 12W#

#W = 22/12 = 11/6 " ft" = 1 " ft " 10 " inches" = 22 " inches"#

#L = 5W = 5*11/6 = 55/6 = 9 " ft " 2 " inches" = 110 " inches"#

Apr 6, 2017

length: 8
width: 3

Explanation:

#a#=length;
#b#=width;

#a=b+5# --> length is 5 more than the width

#22=2a+2b# --> div all by 2
#11=a+b#
#b=11-a#

#b=11-b-5#
#2b=6#

#b=3#
#a=b+5=3+5=8#

#2*8+2*3=16+6=22# --> CORRECT