How do you evaluate (- 7) ^ { 2} \div ( - 3- - 10) ^ { 2}(7)2÷(310)2?

2 Answers
Apr 6, 2017

Explanation:

First combine the terms in the parenthesis

( -7)^2 / {-3-(-10) }^2 = 49 /(+7)^2 (7)2{3(10)}2=49(+7)2

a negative time a negative = a positive
( -7) xx ( -7) = + 49 (7)×(7)=+49

( -) xx ( - 10) = + 10()×(10)=+10

-3 + 10 = +73+10=+7

49/(+7)^2 = 49/4949(+7)2=4949

49/49 = 1 4949=1

Apr 7, 2017

11

Explanation:

(-7)^2-:(-3- -10)^2(7)2÷(310)2

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color(white)(aaaaaaaaaaaaa)aaaaaaaaaaaaa-1010 -
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color(white)(aaaaaaaaaaaaaa)aaaaaaaaaaaaaa+7+7

:.(-7 xx -7)-:(7)^2

:.(-7 xx -7)-:7 xx 7

:.49-:49=1