How do you multiply $(t^{2} + 0.5) (t^{2} - 0.5)$ $(t^2+0.5)(t^2-0.5)$ ?

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How do you multiply $(t^{2} + 0.5) (t^{2} - 0.5)$ $(t^2+0.5)(t^2-0.5)$ ?

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Answer 1 · 2017-04-09T01:51:56

Use distributive property

Explanation:

$(t^{2} + 0.5) (t^{2} - 0.5)$ $(t^2+0.5)(t^2−0.5)$

We have to multiply $(t^{2} + 0.5)$ $(t^2+0.5)$ into $(t^{2} - 0.5)$ $(t^2−0.5)$

So, $t^{2} \cdot t^{2}$ $t^2 * t^2$ which is $t^{4}$ $t^4$ as when you multiply powers with the same base you add the exponents. Then it is $t^{2} \cdot - 0.5$ $t^2 * -0.5$ which $- 0.5 t^{2}$ $−0.5t^2$

Then, $+ 0.5 \cdot t^{2}$ $+0.5*t^2$ which is $0.5 t^{2}$ $0.5t^2$ . Next, $+ 0.5 \cdot - 0.5$ $+0.5*-0.5$ which is $- .25$ $-.25$

Therefore we have,

$t^{4} - 0.5 t^{2} + 0.5 t^{2} - 0.25$ $t^4−0.5t^2+0.5t^2-0.25$

Now all we have to do is combine like terms and the final answer is $t^{4} - 0.25$ $t^4−0.25$

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How do you multiply $(t^{2} + 0.5) (t^{2} - 0.5)$ $(t^2+0.5)(t^2-0.5)$ ?

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Explanation:

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How do you multiply (t^2+0.5)(t^2-0.5)(t2+0.5)(t2−0.5)(t^2+0.5)(t^2-0.5)?

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How do you multiply $(t^{2} + 0.5) (t^{2} - 0.5)$ $(t^2+0.5)(t^2-0.5)$ ?