How do you find f(2/3) given $f (x) = 3 x - 5$ $f(x)=3x-5$ ?

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Answer 1 · 2017-04-10T17:58:28

$f (\frac{2}{3}) = - 3$ $f(2/3)=-3$

$f (\frac{2}{3}) = 3 \cdot (\frac{2}{3}) - 5 = 2 - 5 = - 3$ $f(2/3)=3*(2/3)-5=2-5=-3$

Answer 2 · 2017-04-10T18:01:30

$f (\frac{2}{3}) = - 3$ $f(2/3)=-3$

$f (\frac{2}{3}) = 3 \cdot (\frac{2}{3}) - 5$ $f(2/3)=3*(2/3)-5$
$= 2 - 5$ $=2-5$
=-3

How do you find f(2/3) given f(x)=3x-5f(x)=3x−5f(x)=3x-5?