How do you find the slope of -3x=6y-2?

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How do you find the slope of -3x=6y-2?

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Answer 1 · 2017-04-11T16:13:46

general eq of a line is $y = m x + c$ $y=mx+c$

Explanation:

the general equation of a line is : $y = m x + c$ $y=mx+c$ where m is the slope of the line .
given is the equation of line : $- 3 x = 6 y - 2$ $-3x=6y-2$
rearrange it into the standard equation :
$- 3 x = 6 y - 2$ $-3x=6y-2$
$- 3 x + 2 = 6 y$ $-3x+2=6y$
$- \frac{1}{2} x + \frac{1}{3} = y$ $-1/2x + 1/3 = y$
now compare this equation with the standard equation to obtain slope of line = $- \frac{1}{2}$ $-1/2$

Answer 2 · 2017-04-11T16:16:23

$m = - \frac{1}{2}$ $m = -1/2$

Explanation:

Rearrange the equation into slope intercept form $y = m x + b$ $y = mx + b$ :

$- 3 x = 6 y - 2$ $-3x = 6y - 2$

Add 2 to both sides:

$- 3 x + 2 = 6 y$ $-3x + 2 = 6y$

Divide both sides by 6:

$y = - \frac{3}{6} x + \frac{2}{6}$ $y = -3/6x +2/6$

Simplify:

$y = - \frac{1}{2} x + \frac{1}{3}$ $y = -1/2 x + 1/3$

slope $= m = - \frac{1}{2}$ $= m = -1/2$

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How do you find the slope of -3x=6y-2?

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