How do you solve #3+ 3y = - 3#?

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Answer 1 · 2017-04-12T01:25:31

The answer is #-2.#

#3 + 3y = -3#

First, subtract #3# from both sides of the equation.

#3 -3 + 3y = -3 -3#

This gives you the equation:

#3y = -6#

Now, you divide both sides by #3#.

#(3y)/(3)=-6/3#

This gives you:

#y=-6/3.#

You can divide #-6# by #3#, which equals #-2.#

So, the answer is:

#y=-2.#