How do you find the derivative of $2x^2+x-1$ ?

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Answer 1 · 2017-04-13T16:20:16

$dy/dx(2x^2+x-1)=4x+1$

Use the power rule $r(a)^(r-1)$ and recall that the derivative of a constant is $0$

Therefore the derivative is,

$dy/dx=2*2x^(2-1)+1x^(1-0)-0$

$dy/dx=4x+1$

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