Question

A weightlifter carefully lowers a 150 kg mass from a height of 1.5 m to the floor in 5 seconds. How much power is used?

Answer 1

441W

Explanation:

`W = (mgh)/t`

Where m is mass
g is 9.8 meters per second per second = `(9.8m)/s^2`
h is height
t is time

Plug in the variables

`(150kg xx 9.8"m/s"^2 xx 1.5m)/(5sec) = 441W`