How do you find the domain and range of $f (x) = \sqrt{x - 9}$ $f(x) = sqrt(x-9)$ ?

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Answer 1 · 2017-04-17T00:30:17

Domain ${x : x \geq 9}$ ${x:x>=9}$
Range ${y : y \geq 0}$ ${y:y>=0}$

The value of $x$ $x$ cannot be less than 9, otherwise, the function would be complex ( not a real function).

How do you find the domain and range of f(x) = sqrt(x-9)f(x)=√x−9f(x) = sqrt(x-9)?