How do you factor and solve $x^{2} + 5 x - 2 = 0$ $x^2+5x-2=0$ ?

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How do you factor and solve $x^{2} + 5 x - 2 = 0$ $x^2+5x-2=0$ ?

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Answer 1 · 2017-04-17T01:09:27

$x = - \frac{5}{2} + \frac{\sqrt{33}}{2}$ $x = -5/2 + sqrt(33)/2$ and $x = - \frac{5}{2} - \frac{\sqrt{33}}{2}$ $x = -5/2 -sqrt(33)/2$

Explanation:

Use quadratic formula: $x = \frac{- b + \sqrt{b^{2} - 4 \cdot a \cdot c}}{2 \cdot a}$ $x = (-b + sqrt(b^2-4*a*c))/{2*a}$ and $x = \frac{- b - \sqrt{b^{2} - 4 \cdot a \cdot c}}{2 \cdot a};$ $x = (-b - sqrt(b^2-4*a*c))/{2*a};$ where $a = 1, b = 5; c = - 2 .$ $a = 1, b = 5; c = -2.$

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How do you factor and solve $x^{2} + 5 x - 2 = 0$ $x^2+5x-2=0$ ?

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