How do you factor completely 169x^2 – 64?

2 Answers
Apr 17, 2017

See the entire solution process below:

Explanation:

This problem is a special form of this rule:

(a + b)(a + b) = a^2 - b^2 or a^2 - b^2 = (a + b)(a - b)

If we let a = 13x and let b = 8 and substitute we get:

169x^2 - 64 = (13x + 8)(13x - 8)

Apr 17, 2017

You may notice that both 169and64 are squares.

Explanation:

=13^2*x^2-8^2

=(13x)^2-8^2

We now use the special product A^2-B^2harr(A+B)(A-B)

=(13x+8)(13x-8)