How do you find the equation of the tangent line to the curve #y=x^2e^-x# at (1, 1/e)?
1 Answer
Apr 20, 2017
Explanation:
By Product Rule,
To find an equation of a line, we need two things:
- Point:
#(x_1,y_1)=(1,1/e)# - Slope:
#m=y'(1)=(2-1)cdot1cdot e^{-1}=1/e#
By Point-Slope Form:
By adding
I hope that this was clear.