Question #0ea67

1 Answer
Apr 24, 2017

8.18 * 10^23 atms8.181023atms of nickel with significant figures.

Explanation:

Use dimensional analysis and Avogadro's number:
79.7 * ((1mol)/(58.69g)) *((6.022*10^23 atms)/(1mol))79.7(1mol58.69g)(6.0221023atms1mol)

Then plug it into a calculator to get the answer:
8.18 * 10^23 atms8.181023atms of nickel with significant figures.

***In case you were wondering, 58.69 g is the mass of one mole of Nickel (you can get this from the periodic table).