Question

What is the equation for the line that is parallel to `3x-2y=-6` and passes through the point `(8, 16)`?

Answer 1

`y=(3/2)x+4`
graph{(3/2)x+4 [-0.89, 35.18, 9.42, 27.44]}

Explanation:

`3x-2y=-6`
`-2y=-3x-6`
`y=(3/2)x+3`

The slope `(3/2)` is the same because the line is parallel. Plug the in numbers to find `b`, which is the y-intercept of the new line.

`y=(3/2)x+b`
`16=(3/2)8+b`
`16=12+b`
`4=b`

So the new equation is...
`y=(3/2)x+4`