How do you multiply #(t-3)(t^2+3t+9)#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Deepak G. Apr 27, 2017 #=t^3-27# Explanation: #a^3-b^3=(a-b)(a^2+ab+b^2)# Similarly #(t-3)(t^2+3t+9)# can be written as #t^3-3^3# #=t^3-27# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 1464 views around the world You can reuse this answer Creative Commons License