How do you find the product of $(x^2-3)(2x^2+4x-5)$ ?

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Answer 1 · 2017-04-27T16:31:25

$2x^4+4x^3-11x^2-12x+15$

Multiply each term of $2x^2+4x-5$ by $x^2$
$(2x^4+4x^3-5x^2)-3(2x^2+4x-5)$

Multiply each term of $2x^2+4x-5$ by $-3$
$2x^4+4x^3-5x^2-6x^2-12x+15$

Simplify to get
$2x^4+4x^3-11x^2-12x+15$ #

How do you find the product of (x^2-3)(2x^2+4x-5)(x^2-3)(2x^2+4x-5)?