How much work would it take to horizontally accelerate an object with a mass of $8 k g$ $8 kg$ to $7 \frac{m}{s}$ $7 m/s$ on a surface with a kinetic friction coefficient of $2$ $2$ ?

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How much work would it take to horizontally accelerate an object with a mass of $8 k g$ $8 kg$ to $7 \frac{m}{s}$ $7 m/s$ on a surface with a kinetic friction coefficient of $2$ $2$ ?

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Answer 1 · 2017-04-29T06:12:19

Wrong question ..?

Explanation:

For the body to be accelerated to 7 $m s^{- 1}$ $ms^(-1)$
we know , work don't in doing so is equal to
W= $F \cdot d S = \frac{1}{2} M (v_{f}^{2} - v_{i}^{2})$ $F*dS=1/2M(v_f^2-v_i^2)$

This can be altered due the presence of friction force.
$(F_{a p p l i e d} - K_{f} \cdot N) \cdot d S = \frac{1}{2} M (v_{f}^{2} - v_{i}^{2})$ $(F_(applied)-K_f*N)*dS=1/2M(v_f^2-v_i^2)$

To solve this question we have to get at least 1 variables , But here we have got 2 , provided the information is insufficient.

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How much work would it take to horizontally accelerate an object with a mass of $8 k g$ $8 kg$ to $7 \frac{m}{s}$ $7 m/s$ on a surface with a kinetic friction coefficient of $2$ $2$ ?

1 Answer

Explanation:

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How much work would it take to horizontally accelerate an object with a mass of $8 k g$ $8 kg$ to $7 \frac{m}{s}$ $7 m/s$ on a surface with a kinetic friction coefficient of $2$ $2$ ?