Question

Question #1ef6f

Answer 1

In first case, because `L = lambda_1/2`, the fund freq is `f_1 = v/ lambda_1 = v/(2L)`

In second case, because `(3L)/4 = lambda_2/4`, the fund freq is `f_2 = v/ lambda_2 = v/(3L)`

So `f_2 = 2/3 f_1 = 260 Hz`