Question #7ab87

1 Answer
Apr 30, 2017

#x=3#

Explanation:

Notice that the equation is of the form

#x^2-sx+p#

where #s=a+b# and #p=ab#, in this case #a=3,b=4#. So we have that the polynomial factorises as

#(x-a)(x-b)=0#

hence the roots are #3# and #4#, so the lesser root is #x=3#

If you don't see it straightforward, don't worry: you can proceed with the standard formula for finding roots of quadratic equations:

#x_{12}=(spm sqrt(s^2-4p))/2=(7pm sqrt(49-48))/2 Rightarrow x_1=3, x_2=4#