What is the pOH of a solution with an [OH-] concentration of $9.2 x 10^{- 8}$ $9.2 x 10^-8$ M?

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Answer 1 · 2017-04-30T21:53:31

Use the formula, pOH = -log[OH-]

All you have to do is plug in the value that is given to you for concentration and take the negative log of that number. Then you're good!

What is the pOH of a solution with an [OH-] concentration of 9.2x10−89.2 x 10^-8 M?