Question

Question #0c74b

Answer 1

`sin(9480^@)=sin(120^@)=sqrt(3)/2`

Explanation:

(I have assumed you have wrote the angle in degrees rather than radians although there isn't a degree symbol)
We can first start by simplifying the expression inside the sine function:
`sin(90^@*105^@+30^@)=sin(9450^@+30^@)=sin(9480^@)`
Here we must find the reference angle of `9480^@`:
Since `360^@` is one full circle around the unit circle, we can do:
`9480 mod 360 = 120` to find the remainder when 9480 is divided by 360.
Therefore `sin(9480^@)=sin(120^@)=sqrt(3)/2`