How do you solve the system of equations $-4x - 8y = - 16$ and $4x + 6y = 2$ ?

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Answer 1 · 2017-05-08T16:02:42

$y=7$
$x=-10$

Use the process of elimination. Add the two equations together. You should get:

$-2y=-14$

Solve for $y$ :

$y=7$

Plug this in to one of the original equations. I'll plug it in to the second one:

$4x+6(7)=2$

Solve for $x$ :

$4x=-40$

$x=-10$

Check by plugging into the other equation:

$-4(-10)-8(7)=-16$

$40-56=-16$

$-16=-16$

How do you solve the system of equations -4x - 8y = - 16-4x - 8y = - 16 and 4x + 6y = 24x + 6y = 2?