Question

If the length of the equal two sides of a isosceles triangle is 20 cm and the angle between those two sides is 45 degrees, then what is the area of the triangle?

Answer 1

`100 sqrt2` `unit^2`

Explanation:

Area of triangle `=1/2 bc sin A` where `A = 45^@, b = c =20cm`

Area of triangle = `1/2 *20*20*sin 45^@= 200*1/sqrt2=200/sqrt2 =100 sqrt2`