How do you solve the system of equations #6x - 6y = 18# and #x + 2y = 6#?

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Answer 1 · 2017-05-08T19:26:54

#y=1#

#x=4#

First, take the second equation and subtract #2y# from both sides:
#x=6-2y#

Substitute this value in for #x# for the first equation:
#6(6-2y)-6y=18#

Distribute the #6# to #(6-2y)#:
#36-12y-6y=18#

Combine like terms:
#36-18y=18#

Subtract #36# from both sides:
#-18y=-18#

Divide both sides by #-18# to isolate #y#:
#y=1#

Substitute #1# in for #y# in either equation to solve for #x#:
#x+2(1)=6# #-># #x+2=6# #-># #x=4#