How do you solve the system of equations 2x + 6y = 142x+6y=14 and 4x = 164x=16?

1 Answer
May 12, 2017

Reduce each equation then substitute the second equation into the first equation. Answer: (4,1)(4,1)

Explanation:

Original equation: Given 2x+6y=142x+6y=14 and 4x=164x=16, solve for (x,y)(x,y)

We can solve this system of equations by using substitution. First, we can divide the first equation by 22 and the second equation by 44:
x+3y=7x+3y=7
x=4x=4

Now, we simply substitute the second equation, x=4x=4, into the first equation:
4+3y=74+3y=7
We can subtract 44 from both sides to isolate the 3y3y:
4+3y-4=7-44+3y4=74
3y=33y=3
Now, we divide both sides by 33 to solve for yy:
y=1y=1

Therefore, our solution is the coordinate point (4,1)(4,1)