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Answer 1 · 2017-05-12T14:12:59

No, they cancel out.

Valency is the combining power of an element.

Let's use $C a^{2 +}$ $Ca^(2+)$ and $O^{2 -}$ $O^(2-)$

Valency of $C a^{2 +}$ $Ca^(2+)$ = 2
Valency of $O^{2 -}$ $O^(2-)$ = 2

When they combine, they cancel out into $C a O$ $CaO$ .

(Don't put this on the exam, but you can think of the formula looking like $C a_{2} O_{2}$ $Ca_2O_2$ before they cancel out)

Let's use one more example: $K^{+}$ $K^+$ and $O^{2 -}$ $O^(2-)$

Valency of $K^{+}$ $K^+$ = 1
Valency of $O^{2 -}$ $O^(2-)$ = 2

When they combine, we basically switch the valencies so that the 2 goes by the $K$ $K$ and the 1 goes by the $O$ $O$

So $K_{2} O_{1}$ $K_2O_1$ but the 1 is understood so we don't write that in the final formula which is $K_{2} O$ $K_2O$