How do you solve $2 x - 3 + 6 x = 77$ $2x - 3+ 6x = 77$ ?

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Answer 1 · 2017-05-14T02:47:37

$x = 10$ $x=10$

The method used in solving this kind of equations is to group the unknown terms to one side ie. moving the $x$ $x$ terms.

Start by adding both Left hand side and right hand side by 3

$2 x - 3 + 6 x + 3 = 77 + 3$ $2x-3+6x+3=77+3$

$2 x + 6 x = 80$ $2x+6x=80$

$8 x = 80$ $8x=80$

Next, divide both LHS and RHS by $8$ $8$

$\frac{8 x}{8} = \frac{80}{8}$ $(8x)/8=80/8$

$x = 10$ $x=10$

How do you solve 2x−3+6x=772x - 3+ 6x = 77?