How do you solve $x^{2} - 20 x + 100 = 28$ $x^ { 2} - 20x + 100= 28$ ?

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How do you solve $x^{2} - 20 x + 100 = 28$ $x^ { 2} - 20x + 100= 28$ ?

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Answer 1 · 2017-05-14T18:48:05

$S = {10 \pm 2 \sqrt{7}}$ $S = {10 +- 2sqrt7}$

Explanation:

$x^{2} - 20 x + 100 = 28$ $x^2 - 20x + 100 = 28$
Factorize
$\Leftrightarrow {(x - 10)}^{2} = 28$ $<=> (x-10)^2 = 28$
$\Leftrightarrow x - 10 = \sqrt{28}$ $<=> x-10 = sqrt28$ or $x - 10 = - \sqrt{28}$ $x-10 = -sqrt28$
$\Leftrightarrow x = 10 + 2 \sqrt{7}$ $<=> x=10+2sqrt7$ or $x = 10 - 2 \sqrt{7}$ $x=10-2sqrt7$

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How do you solve $x^{2} - 20 x + 100 = 28$ $x^ { 2} - 20x + 100= 28$ ?

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How do you solve x2−20x+100=28x^ { 2} - 20x + 100= 28?

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Explanation:

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How do you solve $x^{2} - 20 x + 100 = 28$ $x^ { 2} - 20x + 100= 28$ ?