Question

How do you find the zeros, real and imaginary, of `y=-x^2+7x+12` using the quadratic formula?

Answer 1

`x=7/2+sqrt97/2`
or
`x=7/2-sqrt97/2`

Explanation:

Let my awesome notebook explain :D
(I can't be bothered with all the symbols on Socratic so I'll just do it on paper and then take a photo)

The roots, or the zeros of this question is real because the discriminant is positive. The discriminant is the `sqrtb^2-4ac` part.