How do you factor $3 h^{2} - 30 h - 33$ $3h ^ { 2} - 30h - 33$ ?

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Answer 1 · 2017-05-16T02:57:13

Answer: $3 (h - 11) (h + 1)$ $3(h-11)(h+1)$

Factor $3 h^{2} - 30 h - 33$ $3h^2-30h-33$

First we can see that each term has a common factor of $3$ $3$ which we can factor out:
$= 3 (h^{2} - 10 h - 11)$ $=3(h^2-10h-11)$

Now, we can more easily factor (two numbers multiplied together is -11 and added together is -10):
$= 3 (h - 11) (h + 1)$ $=3(h-11)(h+1)$

How do you factor 3h2−30h−333h ^ { 2} - 30h - 33?