Question #99b0f

1 Answer
May 18, 2017

θ=π6+2n,5π6+2n where n is a whole number.

Explanation:

First, set the two rs equal to each other:

0=12sinθ

Now solve for θ:

1=2sinθ

12=sinθ

θ=sin1(12)

θ=π6+2n,5π6+2n where n is a whole number.