How do you solve $5 x^{2} + 40 x + 75 = 0$ $5x ^ { 2} + 40x + 75= 0$ ?

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Answer 1 · 2017-05-19T02:35:28

$x = {- 3, - 5}$ $x = {-3, -5}$

You could simply the equation by factoring out a $5$ $5$ in each term.

$5 (x^{2} + 8 x + 15) = 0$ $5(x^2 + 8x + 15) = 0$

Dividing both sides by $5$ $5$ gives

$x^{2} + 8 x + 15 = 0$ $x^2 + 8x + 15 = 0$

Factoring...

$(x + 3) \cdot (x + 5) = 0$ $(x + 3) * (x + 5) = 0$

So

$x = {- 3, - 5}$ $x = {-3, -5}$

How do you solve 5x2+40x+75=05x ^ { 2} + 40x + 75= 0?