How do you find the roots, real and imaginary, of $y = 0.5 x^{2} - 0.6 x + 3.659$ $y= 0.5x^2-0.6x +3.659$ using the quadratic formula?

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How do you find the roots, real and imaginary, of $y = 0.5 x^{2} - 0.6 x + 3.659$ $y= 0.5x^2-0.6x +3.659$ using the quadratic formula?

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Answer 1 · 2017-05-20T23:51:03

No real roots

Explanation:

$y = 0.5 x^{2} - 0.6 x + 3.659 = 0$ $y = 0.5x^2 - 0.6x + 3.659 = 0$
$D = d^{2} = b^{2} - 4 a c = 3.6 - 7.32 = - 3.72 < 0$ $D = d^2 = b^2 - 4ac = 3.6 - 7.32 = - 3.72 < 0$ .
Since D < 0, there are no real roots. There are 2 imaginary roots.

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How do you find the roots, real and imaginary, of $y = 0.5 x^{2} - 0.6 x + 3.659$ $y= 0.5x^2-0.6x +3.659$ using the quadratic formula?

1 Answer

Explanation:

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How do you find the roots, real and imaginary, of y=0.5x2−0.6x+3.659y= 0.5x^2-0.6x +3.659 using the quadratic formula?

1 Answer

Explanation:

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How do you find the roots, real and imaginary, of $y = 0.5 x^{2} - 0.6 x + 3.659$ $y= 0.5x^2-0.6x +3.659$ using the quadratic formula?