How do you find the range of $b (x) = - x^{2}$ $b(x)=-x^2$ for the domain (-2,0,3,8)?

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Answer 1 · 2017-05-21T04:11:15

R{0,-4,-9,-64}

Plug in each x into the function.
The value of b(x) will be in your range.

$b (- 2) = - 4$ $b(-2) = -4$
$b (0) = 0$ $b(0) = 0$
$b (3) = - 9$ $b(3) = -9$
$b (8) = - 64$ $b(8) = -64$

Therefore the range is {-4,0,-9,-64}, rearranged to {0,-4,-9,-64}.

How do you find the range of b(x)=−x2b(x)=-x^2 for the domain (-2,0,3,8)?