How do you solve #\sqrt { b - 7} = 4#?
1 Answer
May 22, 2017
Explanation:
First, square both sides.
#(sqrt(b-7))^color(blue)(2) = 4^color(blue)(2)#
By doing this, we eliminated the square root. Now add
#b cancel(- 7 color(green)(+7)) = 4^color(blue)(2) color(green)(+7)#
Now simplify the other side by squaring the
#b = (4*4) + 7#
#b = 16 + 7#
#b = 23#