Question

What is the spectator ion and net ionic equation of `Zn(s)+Ag_2SO_4(aq)->ZnSO_4(aq)+2Ag(s)`?

Answer 1

only sulfate `SO_4^(2-)` is a spectator ion
Zn is oxidised to `Zn^(2+)` in this reaction

Explanation:

sulfate remains as `SO_4^(2-)` throughout this reaction, so is chemically unchanged, so is a "spectator" in the transfer of electrons (otherwise known as chemistry!)
Zn begins the reaction as elemental Zinc (`Zn^0`) and ends the reaction as `Zn^(2+)` , so loses 2 electrons, so oxidation.
Ag begins the reaction as ionic Ag (`Ag^(1+)`) and ends the reactions as elemental Silver (`Ag^0`), so gains 1 electron, so reduced.