Question

How do you differentiate `y=e^(ktansqrtx)`?

Answer 1

Derivative = `k/2 x^(-1/2) sec^2(sqrtx)e^(ktan(sqrtx)`

Explanation:

If `f(x) = e^(g(x))` then `f'(x) = g'(x)e^(g(x))`