How do you simplify $\frac{{(w^{3})}^{2} {(w^{4})}^{5}}{{(w^{4})}^{2}}$ $\frac { ( w ^ { 3} ) ^ { 2} ( w ^ { 4} ) ^ { 5} } { ( w ^ { 4} ) ^ { 2} }$ ?

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Answer 1 · 2017-05-24T13:40:15

$w^{18}$ $w^18$

You would simplify the exponents

${(w^{3})}^{2} = w^{6}$ $(w^3)^2 = w^6$
${(w^{4})}^{5} = w^{20}$ $(w^4)^5 = w^20$
${(w^{4})}^{2} = w^{8}$ $(w^4)^2 = w^8$

You end up with this:

$\frac{w^{6} \cdot w^{20}}{w^{8}}$ $(w^6* w^20)/w^8$

Using multiplication exponent rule:

$\frac{w^{26}}{w^{8}}$ $(w^26)/w^8$

Using division exponent rule and you end up with this:

$w^{18}$ $w^18$

How do you simplify (w3)2(w4)5(w4)2\frac { ( w ^ { 3} ) ^ { 2} ( w ^ { 4} ) ^ { 5} } { ( w ^ { 4} ) ^ { 2} }?