How do you solve $\frac{3}{5} d + 5 = \frac{1}{3} d - 3$ $3/5d+5=1/3d-3$ ?

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Answer 1 · 2017-05-26T18:39:24

d = - 30

My own work (Mert METİN)

Answer 2 · 2017-05-26T18:55:30

$d = - 30$ $color(green)(d=-30$

$\frac{3}{5} d + 5 = \frac{1}{3} d - 3$ $3/5d+5=1/3d-3$

$:.3/5d+25/5=1/3d-9/3$

$:.3/5d-1/3d=-9/3-25/5$

multiply L.H.S andR.H.S.by 15

$:.15(3/5d)-15(1/3d)=15(-9/3)-15(25/5)$

$:.9d-5d=-45-75$

$:.4d=-120$

$:.color(green)(d=-30$

substitute $color(green)(d=-30$

$:.3/5(-30)+5=1/3(-30)-3$

$:.-18+5=-10-3$

$:.color(green)(-13=-13$

How do you solve 3/5d+5=1/3d-335d+5=13d−33/5d+5=1/3d-3?