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Answer 1 · 2017-05-27T05:41:40

.

P = force/area $=(kgms^-2)/m^2= kgm^-1s^-2$
v $= ms^-1$
A $=m^2$

$Q= (kgm^-1s^-2)/(ms^-1 m^2)$

$Q=kgm^(-1-3)s^(-2-(-1)$

$Q=kgm^-4s^-1$

Answer 2 · 2017-05-27T05:42:12

$Kgm^-4sec^-1$

See , ATQ

$Q=(P)/(v*A)$
$=>(F/A)/(m/s*A)$
$=>(F)/(v*A^2)$
$=>(MLT^(-2))/(LT^(-1)*L^5)$

$=>(MLT^-2)/(L^5T^-1)=ML^-4T^-1$

hence , equals to $Kgm^-4sec^-1$