How do you write $2 x^{5} - 12 + 3 x$ $2x^5-12+3x$ in standard form?

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Answer 1 · 2017-05-29T14:06:03

Polynomials in standard form are written with the highest exponent first, followed by the lower exponents, ending with the constant :)

No need to do anything other than rearrange the numbers:

$f (x) = 2 x^{5} + 3 x - 12$ $f(x) = 2x^5+3x-12$

Ohh, but I almost forgot. To stay true to the standard form, you should write

$2 x^{5} + 3 x - 12 = 0$ $2x^5+3x-12 = 0$

:D

How do you write 2x5−12+3x2x^5-12+3x in standard form?