How do you write the equation #y+2=7/8(x-3)# in standard form?
2 Answers
That equation in standard form is
Explanation:
First, you can distribute the
After that subtract both sides by two:
Explanation:
#"the equation of a line in "color(blue)"standard form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#
where A is a positive integer and B, C are integers.
#"rearrange " y+2=7/8(x-3)" into this form"#
#rArry+2=7/8x-21/8larrcolor(red)" distributing"#
#"subtract " 7/8x" from both sides"#
#y+2-7/8x=cancel(7/8x)cancel(-7/8x)-21/8#
#rArry+2-7/8x=-21/8#
#"subtract 2 from both sides"#
#ycancel(+2)cancel(-2)-7/8x=-21/8-2#
#rArry-7/8x=-37/8#
#"multiply through by " -8#
#rArr7x-8y=37larrcolor(red)" in standard form"#