How do you solve $\frac { y - 1} { 3} = \frac { y + 1} { 6}$ ?

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Answer 1 · 2017-05-30T06:00:28

$y=3$

$(y-1)/3=(y+1)/6$

To proceed, the fractions have to be changed to share the same common denominator.

Multiply each side by their lowest common multiple, $3*6=18$

$18$ x $(y-1)/3=(y+1)/6$ x $18$

$(6(y-1))/1=(3(y+1))/1$

Now they share the same denominator of 1.

$6y-6=3y+3$

$6y-3y=3+6$

$3y=9$

$y=9/3 =3$

How do you solve \frac { y - 1} { 3} = \frac { y + 1} { 6}\frac { y - 1} { 3} = \frac { y + 1} { 6}?