How do you find #(f+h)(0)# given #f(x)=x^2-1 and #g(x)=2x-3# and #h(x)=1-4x#?

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Answer 1 · 2017-06-01T21:44:08

See below.

#(f+h)(0)=f(0)+h(0)#.

Given that #f(x)=x^2-1#,

#f(0)=0^2-1=-1#

#h(0)=1-4(0)=1#

Thus,

#(f+h)(0)=f(0)+h(0)=-1+1=0#.