How do you solve #3x - 5= 11x - 93#? Algebra Linear Equations Equations with Variables on Both Sides 1 Answer Dan Kemp Jun 2, 2017 #x =11# Explanation: #3x - 5 = 11x - 93# #3x -11x - 5 = - 93# #3x -11x = - 93 + 5# #-8x = - 88# #cancel(-)8x = cancel(-) 88# #8x =88# #x =88 ÷ 8# #color(blue)(x =11# Now we can substitute #x# for #11# to prove our answer. #3x - 5 = 11x - 93# #3 xx 11 - 5 = 11 xx 11 - 93# #33 - 5 = 121 - 93# #28 = 121 - 93# #121 - 93 = 28# #28 = 28# Answer link Related questions How do you check solutions to equations with variables on both sides? How do you solve #125+20w-20w=43+37w-20w#? How do you solve for x in #3(x-1) = 2 (x+3)#? Is there a way to solve for x without using distribution in #4(x-1) = 2 (x+3)#? How do you solve for t in #2/7(t+2/3)=1/5(t-2/3)#? How do you solve #5n + 34 = −2(1 − 7n)#? How do you simplify first and then solve #−(1 + 7x) − 6(−7 − x) = 36#? Why is the solution to this equation #-15y + 7y + 1 = 3 - 8y#, "no solution"? How do you solve for variable w in the equation #v=lwh#? How do you solve #y-y_1=m(x-x_1)# for m? See all questions in Equations with Variables on Both Sides Impact of this question 1856 views around the world You can reuse this answer Creative Commons License