How do you arrange NH+4,BF3,H2O,C2H2, in increasing order of bond angle?

1 Answer
Jun 5, 2017

Determine Geometry of each.
NH+4θb=109o
BF3θb=120o
H2Oθb=105o
C2H2HCCHθb=180o

H2O<NH+4<BF3<C2H2 about both carbon centers.

Explanation:

Geometry of HOH => AX2E2 => Bent angular from an AX4 Tetrahedral Parent. The 2 free pair repel the 2 bonded pair to compress the bond angle from 109o in a tetrahedron to 105o => Bent Angular Geometry.

Geometry of NH+4 is AX4 tetrahedral => θb=109o

Geometry of BF3 is AX3 Trigonal Planar AX3 => θb=120o

Geometry of C2H2 is linear through two carbon centers.
=> HCCHθb=180o