How do you factor $36x ^ { 4} - 27x ^ { 3} + 45x ^ { 2}$ ?

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Answer 1 · 2017-06-07T02:58:04

$9x^2(4x^2-3x+5)$

To factor out the problem we need to figure out the factor of $35,-27, and 45$ .

$9$ is our magic number, we also need to factor out $x$ to do this we get the smallest amount of $x$ that is available which is $x^2$ .

So, our factor is $9x^2$ .

$9x^2(4x^2-3x+5)$ is the answer. To check this you can distribute it out and you will arrive to the original problem.

How do you factor 36x ^ { 4} - 27x ^ { 3} + 45x ^ { 2}36x ^ { 4} - 27x ^ { 3} + 45x ^ { 2}?